Calculate Normality

Normality
0.1000 N
0.1000 eq/L = 0.1000 mol/L (for 1:1 reactions)

Formula

Normality (N) = equivalents of solute / volume of solution (L)
Equivalents = mass (g) / equivalent weight (g/eq)

N = mass / (eq_weight × volume)

Formula variables

  • N — normality in equivalents per liter (eq/L).
  • mass — mass of solute in grams.
  • eq_weight — equivalent weight in grams per equivalent.
  • volume — volume of solution in liters.

Equivalent Weight

Equivalent weight depends on the reaction type:

  • Acids: Molar mass ÷ basicity (number of H⁺ ions). HCl = 36.46 ÷ 1 = 36.46 g/eq. H₂SO₄ = 98.08 ÷ 2 = 49.04 g/eq.
  • Bases: Molar mass ÷ acidity (number of OH⁻ ions). NaOH = 40.00 ÷ 1 = 40.00 g/eq. Ca(OH)₂ = 74.09 ÷ 2 = 37.05 g/eq.
  • Salts: Molar mass ÷ (charge of cation × number of cations). Na₂CO₃ = 105.99 ÷ 2 = 53.00 g/eq.
  • Redox: Molar mass ÷ number of electrons transferred.

Worked Examples

Example 1: Preparing 0.1 N NaOH

  1. Mass: 4.00 g NaOH.
  2. Equivalent weight: 40.00 g/eq.
  3. Volume: 1.00 L.
  4. N = 4.00 / (40.00 × 1.00) = 0.1000 N.

Example 2: Titration of HCl with NaOH

25.00 mL of HCl requires 20.00 mL of 0.1000 N NaOH to reach the endpoint. What is the normality of the HCl?

  1. Equivalents of NaOH = 0.1000 × 0.02000 = 0.002000 eq.
  2. Equivalents of HCl = 0.002000 eq (1:1 stoichiometry).
  3. Volume of HCl = 0.02500 L.
  4. Normality = 0.002000 / 0.02500 = 0.08000 N.

Example 3: 0.5 M H₂SO₄ → normality

  1. Molarity: 0.5 M.
  2. H₂SO₄ has 2 acidic hydrogens per molecule.
  3. Normality = 0.5 × 2 = 1.0 N.

Example 4: Redox — KMnO₄ in acidic solution

  1. Molar mass: 158.03 g/mol.
  2. In acidic solution, Mn⁷⁺ is reduced to Mn²⁺, a 5-electron transfer.
  3. Equivalent weight = 158.03 ÷ 5 = 31.61 g/eq.
  4. For a 0.02 M solution, normality = 0.02 × 5 = 0.1 N.

Relationship Between N and M

N = M × n

Where n is the number of equivalents per mole (basicity, acidity, or electron transfer). For 1:1 reactions, N = M.

n factors for common substances
Substancen (eq/mol)
HCl1
HNO₃1
H₂SO₄ (full neutralization)2
H₃PO₄ (full neutralization)3
NaOH1
Ca(OH)₂2
Na₂CO₃2
KMnO₄ (acidic)5
KMnO₄ (neutral)3
K₂Cr₂O₇ (acidic)6

Real-World Uses

  • Acid-base titrations: Normality simplifies calculations because equivalents react 1:1 (N₁V₁ = N₂V₂).
  • Redox titrations: Normality expresses electron-transfer capacity.
  • Water treatment: Water hardness and alkalinity are sometimes expressed in equivalents per liter.
  • Environmental chemistry: Acid neutralizing capacity (ANC) is expressed in eq/L.
  • Industrial processes: Historic industrial chemistry uses normality; modern practice prefers molarity.

Unit Definitions

Normality (N)

The concentration of a solution expressed as equivalents of solute per liter of solution. An equivalent is the amount of substance that reacts with or supplies one mole of hydrogen ions (for acid-base reactions), or one mole of electrons (for redox reactions).

Related Converters

Frequently Asked Questions

What is normality?

Normality (N) is the concentration of a solution expressed as equivalents of solute per liter of solution. It is used in titrations where reactions follow equivalent ratios.

How do you calculate normality?

Divide the number of equivalents of solute by the volume of solution in liters: N = eq / V. Alternatively, N = mass / (equivalent weight × volume).

How do you convert molarity to normality?

N = M × n, where n is the number of equivalents per mole. For HCl, n = 1 (N = M). For H₂SO₄, n = 2 (N = 2M).

Why is normality less used than molarity?

Because the equivalent depends on the specific reaction. A solution of H₂SO₄ can be 1 M and 2 N (full neutralization) or 1 M and 1 N (partial). Molarity is unambiguous, so modern practice prefers it.

What is 1 N HCl in molarity?

1 N HCl = 1 M HCl because HCl has one acidic hydrogen per molecule (n = 1).